将y等于x+1除以x-2改为用y的代数式表示x的形式

问题描述:

将y等于x+1除以x-2改为用y的代数式表示x的形式

解:
y=(x+1)/(x-2)=(x-2+3)/(x-2)
=1 + 3/(x-2)
y-1=3/(x-2)
x-2=3/(y-1)
x=3/(y-1) + 2

x=(2y+1)/(y-1)

y=(x+1)/(x-2)
y(x-2)=x+1
xy-2y=x+1
xy-x=2y+1
x(y-1)=2y+1
x=(2y+1)/(y-1)

y=(x+1)÷(x-2)
y(x-2)=x+1
xy-2y=x+1
xy-x=2y+1
(y-1)x=2y+1
x=(2y+1)/(y-1)