a的5次方-a,
问题描述：
a的5次方-a,
答
a^5-a
＝a(a^4-1)
＝a(a²+1)(a²-1)
＝a(a²+1)(a+1)(a-1).
答
a^5-a=a(a^4-1)=a(a^+1)(a^2-1)=a(a+1)(a-1)(a^2+1)
答
原式=a9a⁴-1)
=a(a²+1)(a²-1)
=a(a²+1)(a+1)(a-1)