请问:无穷等比数列{an}的前n项和是S=a1/(1-q)还是Sn=a1(1-q^n)/(1-q)?请问:无穷等比数列{an}的前n项和是S=a1/(1-q)还是Sn=a1(1-q^n)/(1-q)?

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请问:无穷等比数列{an}的前n项和是S=a1/(1-q)还是Sn=a1(1-q^n)/(1-q)?
请问:无穷等比数列{an}的前n项和是S=a1/(1-q)还是Sn=a1(1-q^n)/(1-q)?

无穷等比数列{an}的前n项和是Sn=a1(1-q^n)/(1-q)?.当q〈1且n趋近于无穷大时(1-q^n)趋近于1,此时为 Sn=a1/(1-q).查看原帖>>