在等差数列{an}中,已知a1+a2+…+a100=35,a101+a102+…+a200+120,那么a201+a202+…+300=?答案是205.请问为什么,

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• 在等差数列{an}中,已知a1+a2+…+a100=35,a101+a102+…+a200+120,那么a201+a202+…+300=?答案是205.请问为什么,
• 在等差数列{an}中,已知a1+a2+…+a100=35,a101+a102+…+a200+120,那么a201+a202+…+300=?
• {an}中,已知log2^a(n+1)=1+log2^an,且a1+a2+……+a100=100,则a101+a102+……+a200=?
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