A math question,please.I have to result this question by my exam,could any one help me?question:A car park measures 15 metres by 18 metres.A car occupies 6 square metres but two-fifths of the park must be left free for turing.What is the maximum cpacity of the car park?A.18 B.3 C.36 D.9 E 27I see the answer for E.i don't understand a lot.thanks for everybody who could get us a reasonable answer.Thank you!如果复杂就用CHINESE吧,我的英文understanding比较limited
A math question,please.
I have to result this question by my exam,could any one help me?
question:
A car park measures 15 metres by 18 metres.A car occupies 6 square metres but two-fifths of the park must be left free for turing.What is the maximum cpacity of the car park?
A.18 B.3 C.36 D.9 E 27
I see the answer for E.i don't understand a lot.
thanks for everybody who could get us a reasonable answer.
Thank you!
如果复杂就用CHINESE吧,我的英文understanding比较limited
整个停车场面积是15x18=270平米。五分之二不能用， 那它的五分之三是162平米。一俩车占6平米， 162除6等于27。所以整个停车场可以听27辆车
停车场面积：15x18=270 square metres.其中五分之二的面积要预留用来倒车。所以可用的停车面积为270x0.6=162.
一辆车占用面积6平米。可以停的车数为162/6=27辆。
For each car,the real space is not 6,but 6 /(3/5) = 10
Then total number of cars in this parking lot:
15*18/10 = 3x9 = 27