分解　2x＾3－4x＾2y－x＾2z＋2xy＾2＋2xyz－y＾2z求过程

2x³－4x²y－x²z＋2xy²＋2xyz－y²z
=(2x³-4x²y+2xy²)-(x²z-2xyz+y²z)
=2x(x²-2xy+y²)-z(x²-2xy+y²)
=2x(x-y)²-z(x-y)²
=(x-y)²(2x-z)

2x³－4x²y－x²z＋2xy²＋2xyz－y²z
＝﹙2x³－4x²y＋2xy²﹚－﹙x²z－2xyz＋y²z﹚
＝2x﹙x²－2xy＋y²﹚－z﹙x²－2xy＋y²﹚
＝﹙2x－z﹚﹙x²－2xy＋y²﹚
＝﹙2x－z﹚﹙x－y﹚²

2x＾3－4x＾2y－x＾2z＋2xy＾2＋2xyz－y＾2z
=(2x^3-4x^2y+2xy^2)-(x^2z-2xyz+y^2z)
=2x(x^2-2xy+y^2)-z(x^2-2xy+y^2)
=2x(x-y)^2-z(x-y)^2
=(x-y)^2(2x-z)