cos10°cos110°-cos200°cos100°?
问题描述:
cos10°cos110°-cos200°cos100°?
答
cos10°cos110°-cos200°cos100°
=cos10°cos110°-cos(90+110)°cos(90+10)°
=cos10°cos110°-sin110°sin10°
=cos(10+110)°
=cos120°
=-1/2