因式分解:a²-b²+6b-9

问题描述:

因式分解:a²-b²+6b-9

a²-b²+6b-9=a²-【b²-6b+9】=a²-(b-3)²=(a+b-3)(a-b+3)

a²-b²+6b-9
=a²-(b²-6b+9)
=a²-(b-3)²
=(a+b-3)(a-b+3)

原式=a²-(b²-6b+9)=a²-(b-3)²=(a+b-3)(a-b+3)

a²-b²+6b-9=a²-(b-3)²=(a+b-3)(a-b+3)

a²-b²+6b-9
=a²-(b-3)²
=(a+b-3)(a-b+3)