跪求大神解cos36’cos72‘=
问题描述:
跪求大神解cos36’cos72‘=
答
cos36°cos72°=4cos36°sin18°cos18°/(4cos18°)=sin72°/(4sin72°)=1/4
跪求大神解cos36’cos72‘=
cos36°cos72°=4cos36°sin18°cos18°/(4cos18°)=sin72°/(4sin72°)=1/4