x2+(m-1)x+(m-2)=0,采用分解因式法得:(x+1)(x+m-2)=0,

问题描述:

x2+(m-1)x+(m-2)=0,采用分解因式法得:(x+1)(x+m-2)=0,
怎么来的?

x²+mx-x+m-2=0
(x²-x-2)+mx+m=0
(x-2)(x+1)+m(x+1)=0
(x+1)(x-2+m)=0