(Inx/x+1)+(1/x)-(Inx/x-1)=(1/1-x^2)[2Inx-(x^2-1/x)] 由前推到后的步骤,
问题描述:
(Inx/x+1)+(1/x)-(Inx/x-1)=(1/1-x^2)[2Inx-(x^2-1/x)] 由前推到后的步骤,
答
Inx /(x+1)+(1/x) - Inx /(x-1) @= lnx [ 1/(x+1) + 1/(1-x) ] -1/x= lnx * 2 /(1-x^2) - 1/x [1/(1-x^2)] [2Inx-(x^2-1) / x ] @@= lnx * 2 /(1-x^2) +1/x=> @ = @@