x/{(x+1)(x+2)(x+3)}转化成差的形式怎么转 有没有这类的公式

待定系数原式 = A/(X+1) + B/(X+2) + C/(X+3)= (A(X+2)(X+3) + B(X+1)(X+3) + C(X+1)(X+2))/(X+1)(X+2)(X+3)=>(A+B+C)XX + (5A+4B+3C)X + (6A+3B+2C) = X=>A+B+C=05A+4B+3C=16A+3B+2C=0剩下的你已经可以自行解决...