解一元二次方程:x^2-3ax+2a^2-ab-b^2=0
问题描述:
解一元二次方程:x^2-3ax+2a^2-ab-b^2=0
答
x^2-3ax+2a^2-ab-b^2=0
(x-(a-b))(x-(2a+b))=0
x=a-b
x=2a+b