log3 4/log9 8=?(3、9为底数) 我的答案是1/2,

问题描述:

log3 4/log9 8=?(3、9为底数) 我的答案是1/2,

log3 4/log9 8
=2*log3 2/[(3/2)*log3 2]
=2/(3/2)
=4/3
loga^b(c^d)=d/bloga(c)