求高手解六元二次方程式：y1a^2/x1b^2=(y1-y0)/(x1-x0) y2c^2/x2d^2=(y2-y0)/(x2-x0) (y1-y0)^2+(x1-x0)^2=R^2(y2-y0)^2+(x2-x0)^2=R^2x1^2/a^2+y1^2/b^2=1x2^2/c^2+y2^2/d^2=1已知：a,b,c,d,R求：x0,y0,x1,y1,x2,y2的表达式
问题描述：
求高手解六元二次方程式：
y1a^2/x1b^2=(y1-y0)/(x1-x0)
y2c^2/x2d^2=(y2-y0)/(x2-x0)
(y1-y0)^2+(x1-x0)^2=R^2
(y2-y0)^2+(x2-x0)^2=R^2
x1^2/a^2+y1^2/b^2=1
x2^2/c^2+y2^2/d^2=1
已知：a,b,c,d,R
求：x0,y0,x1,y1,x2,y2的表达式
答
无解 -x +25=5+x x^2+x-20=0 (x+5)(x-4)=0 x1=-5,x2=4(x+5)(x-4)=0 x1=-5, x2=4 5: x +4x-1=0 求根公式：x1=-
答
[x0 y0 x1 y1 x2 y2]=solve('y1*a^2*(x1-x0)=x1*b^2*(y1-y0)','y2*c^2*(x2-x0)=x2*d^2*(y2-y0)','(y1-y0)^2+(x1-x0)^2=r^2','(y2-y0)^2+(x2-x0)^2=r^2','x1^2*b^2+y1^2*a^2=a^2*b^2','x2^2*d^2+y2^2*c^2=c^2*d^2','x0','y0','x1','y1','x2','y2')