计算：【6(x+2)²-8(x+2)(x-2)+10(x+2)】÷2(x+2),结果是否等于19-x?
问题描述：
计算：【6(x+2)²-8(x+2)(x-2)+10(x+2)】÷2(x+2),结果是否等于19-x?
答
结果正确
答
【6(x+2)2-8(x+2)(x-2)+10(x+2)】÷2(x+2)
=6(x+2)2÷2(x+2)-8(x+2)(x-2)÷2(x+2)+10(x+2)÷2(x+2)
=3(x+2)-4(x-2)+5
=3x+6-4x+8+5
=19-x
要采纳哦，O(∩_∩)O！
答
【6(x+2)²-8(x+2)(x-2)+10(x+2)】÷2(x+2)
=6(x+2)²÷2(x+2)-8(x+2)(x-2)÷2(x+2)+10(x+2)÷2(x+2)
=3(x+2)-4(x-2)+5
=3x+6-4x+8+5
=19-x
结果正确
要采纳哦，O(∩_∩)O！
答
【6(x+2)²-8(x+2)(x-2)+10(x+2)】÷2(x+2)
=6(x+2)²÷2(x+2)-8(x+2)(x-2)÷2(x+2)+10(x+2)÷2(x+2)
=3(x+2)-4(x-2)+5
=3x+6-4x+8+5
=19-x
答
【6(x+2)²-8(x+2)(x-2)+10(x+2)】÷2(x+2)
=3(x+2)-4(x-2)+5
=3x+6-4x+8+5
=19-x