问几道有理数算术题①-9÷3+(1/2-2/3)×12+3²②(-3)×(-2)-(-1)的99次幂÷1/2
问题描述:
问几道有理数算术题
①-9÷3+(1/2-2/3)×12+3²
②(-3)×(-2)-(-1)的99次幂÷1/2
答
① -9÷3+(1/2-2/3)×12+3²
原式=-3-1/6×12+9
=-3-2+9
=-5+9
=4
② (-3)×(-2)-(-1)的99次幂÷1/2
原式=6-(-1)÷1/2
=6+2
=8
(-1)的99次幂是-1
答
-9/3+(3/6-4/6)*12+9
=-3+(-1/3)*12+9
=-3+(-4)+9
=-7+9
=2
答
①-9÷3+(1/2-2/3)×12+3²
=-3-2+9
=4
②(-3)×(-2)-(-1)的99次幂÷1/2
=6+1*2
=8