If a2-a=1 and az+a-3 are opposite numbers to each other,and themverse number of a is less than the接着是opposite number of a,then a的2009次方+a的2010次方= (英汉词典:inverse number倒数；opposite相反的)确认是0
问题描述：
If a2-a=1 and az+a-3 are opposite numbers to each other,and themverse number of a is less than the
接着是opposite number of a,then a的2009次方+a的2010次方= (英汉词典:inverse number倒数；opposite相反的)
确认是0
答
a平方-a+1和a平方 +a -3是相反数，a的倒数小于a的相反数
答
0
应该是a平方-a+1和a平方 +a -3是相反数,a的倒数小于a的相反数.
算出a=-1