20(x+3)²=125（x-2）²
问题描述：
20(x+3)²=125（x-2）²
答
20(x+3)²=125（x-2）²
4(x+3)²=25（x-2）²
25（x-2）²-4(x+3)²=0
[5(x-2)-2(x+3)][5(x-2)+2(x+3)]=0
(5x-10-2x-6)(5x-10+2x+6)=0
(3x-16)(7x-4)=0
x=16/3或x=4/7