解x^2-12x+36=0
问题描述:
解x^2-12x+36=0
答
x^2-12x+36=0
(x-6)(x-6)=0
x1=x2=6
解x^2-12x+36=0
x^2-12x+36=0
(x-6)(x-6)=0
x1=x2=6