去括号:a-(b-c)= -(9a+b)-3c= 2a-[3b-(c+d)]= -[-(x+y)]-{-[-(a-b)]}=
问题描述:
去括号:a-(b-c)= -(9a+b)-3c= 2a-[3b-(c+d)]= -[-(x+y)]-{-[-(a-b)]}=
答
a-(b-c)
=a-b+c
-(9a+b)-3c
=-9a-b-3c
2a-[3b-(c+d)]
=2a-3b+(c+d)
=2a-3b+c+d
-[-(x+y)]-{-[-(a-b)]}=
=(x+y)-(a-b)
=x+y-a+b去括号,并合并同类项:7X-(5x-5y)-y=3x-[5x-(二分之一x-3)]=(2x2-3x+1)-(-5+3x+x2)=7X-(5x-5y)-y=7x-5x+5y-y=(7-5)x+(5-1)y=2x+4y3x-[5x-(二分之一x-3)]=3x-5x+x/2-3=-3x/2-3(2x2-3x+1)-(-5+3x+x2)=2x²-3x+1+5-3x-x²=x²-6x+6添括号:2a-b2+c-d3=2a+()-d3-5x3+2x2-7x+4=-( )+42a-b2+c-d3=2a+(-b2+c)-d3-5x3+2x2-7x+4=-( 5x3-2x2+7x )+4