已知x:y:z=2:3:4,且x-y+z=36,求x+y+z的值.

问题描述:

已知x:y:z=2:3:4,且x-y+z=36,求x+y+z的值.

因为x:y:z=2:3:4
所以设x=2k,y=3k z=4k
因为x-y+z=36
所以:2k-3k+4k=36
3k=36
k=12
所以x+y+z
=2k+3k+4k
=9k
=9×12
=108