(z2-x2-y2)2-4x2y2=?因式分解,题中的“2”均为平方,无乘号.
问题描述：
(z2-x2-y2)2-4x2y2=?因式分解,题中的“2”均为平方,无乘号.
答
平方差原式=(z²-x²-y²+2xy)(z²-x²-y²-2xy)=[z²-(x²+y²-2xy)][z²-(x²+y²+2xy)]=[z²-(x-y)²][z²-(x+y)²]=(z+x-y)(z-x+y)(z-x-y)(z+...