5a^3ImI+1-(m+2)b-10是七次二项式,求m^2+m的值
问题描述:
5a^3ImI+1-(m+2)b-10是七次二项式,求m^2+m的值
答
5a^(3ImI+1)-(m+2)b-10是七次二项式,则有:
3ImI+1=7
m+2=0
解得m=-2
m²+m=(-2)²-2=2