32(x·y)^4÷[-8/9(y-x)^3]
问题描述：
32(x·y)^4÷[-8/9(y-x)^3]
答
32(x-y)^4÷[-8/9(y-x)^3]
=32(x-y)^4÷[8/9(x-y)^3]
=32*9/8*(x-y)^4÷(x-y)^3
=36(x-y)
=36x-36y