(1)923−9923+99923=(2)(38+16−29)×72=(3)4.9×512+4.9+312×4.9=(4)9999+99992=(5)11×12×13-12×13-260=(6)101×99×999+999=(7)514×3.8+6.2×5.25=(8)1880×199.9-1999×187.9=

问题描述:

(1)9

2
3
−99
2
3
+999
2
3
=
(2)(
3
8
+
1
6
2
9
)×72
=
(3)4.9×5
1
2
+4.9+3
1
2
×4.9
=
(4)9999+99992=
(5)11×12×13-12×13-260=
(6)101×99×999+999=
(7)5
1
4
×3.8+6.2×5.25
=
(8)1880×199.9-1999×187.9=

(1)9

2
3
−99
2
3
+999
2
3

=(9+999-99)+(
2
3
+
2
3
-
2
3

=909+
2
3

=909
2
3

(2)(
3
8
+
1
6
2
9
)×72

=
3
8
×72+
1
6
×72-
2
9
×72,
=27+12-16,
=23;
(3)4.9×5
1
2
+4.9+3
1
2
×4.9

=4.9×(5.5+1+3.5),
=4.9×10,
=49;
(4)9999+99992
=9999×(1+9999),
=9999×10000,
=99990000;
(5)11×12×13-12×13-260,
=(11-1)×12×13-260,
=10×12×13-260,
=1560-260,
=1300;
(6)101×99×999+999,
=999×(101×99+1),
=999×[(100+1)×99+1];
=999×[100×99+99+1],
=999×[9900+99+1],
=999×10000,
=9990000;
(7)5
1
4
×3.8+6.2×5.25

=5.25×(3.8+6.2),
=5.25×10,
=52.5;
(8)1880×199.9-1999×187.9,
=1880×199.9-199.9×1879,
=(1880-1879)×199.9,
=1×199.9,
=199.9.
答案解析:(1)整数部分相加减,分数部分相加减;
(2)根据乘法分配律约分计算;
(3)提公因数4.9计算;
(4)提公因数,即原式=9999×(1+9999);
(5)原式=12×13×(11-1)-260;
(6)原式=999×(101×99+1)=999×[(100+1)×99+1];
(7)提公因数5.25计算即可;
(8)原式=199.9×(1880-1879).
考试点:分数的四则混合运算;整数四则混合运算;运算定律与简便运算.

知识点:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.