数学题一道,但我有点蒙了,帮详解下哈,

问题描述:

数学题一道,但我有点蒙了,帮详解下哈,
2的负二分之一次方 + (1/√2 )+( 1/√2-1 ) + (-1)等于多少

2^(-1/2)+(1/√2)+(1/√2-1)+(-1)
=(1/2)^(1/2)+1/√2+1/(√2-1)+(-1)
=√(1/2)+√2/2+(√2+1)/(√2-1)(√2+1)-1
=√2/2+√2/2+(√2+1)-1
=√2+√2+1-1
=2√2