sin3(-α)cos(2π+α)tan(-α-π)化简
问题描述:
sin3(-α)cos(2π+α)tan(-α-π)化简
答
sin3(-α)cos(2π+α)tan(-α-π)
=-sin3a*cosa*(-tana)
=sin3a*sina
=
答
sin3(-α)cos(2π+α)tan(-α-π)
=-sin3acosa-tana
=sin3acosatana
=sin3asina