x²-(4-i)x+5-5i=0
问题描述：
x²-(4-i)x+5-5i=0
答
方程：x²-(4-i)x+5-5i=0 ,利用x={-b±√[(b)²-4ac]}/(2a)得此方程的x1={(4-i)+√[(4-i)²-4(5-5i)]}/2=2-(i/2)+√[3i-(5/4)]x2={(4-i)-√[(4-i)²-4(5-5i)]}/2=2-(i/2)-√[3i-(5/4)]又有：√[3i-(...