g(x)=e^x,x0则g(g(1/3))=

问题描述:

g(x)=e^x,x0则g(g(1/3))=

1/3>0
所以g(1/3)=ln(1/3)=-ln3所以g[g(1/3)]=e^]g(1/3)]
=e^[ln(1/3)]
=1/3