把下列式子化为k(x-y)n的形式(要有过程) (1) 3(x-y)³×4(x-y)² (2) 27(x-y)²{-2

问题描述:

把下列式子化为k(x-y)n的形式(要有过程) (1) 3(x-y)³×4(x-y)² (2) 27(x-y)²{-2
(2) 27(x-y)²{-2 /9(y-x)^4}
还有两题是简便计算的
(3/2)^6×8^8
{(1/2)²}^6×(2^3)²

3(x-y)³×4(x-y)²
=12(x-y)^5后面滴捏?27(x-y)²{-2 /9(y-x)^4}=-6(x-y)²(x-y)^4=-6(x-y)^6(3/2)^6×8^8=3^6*8^8/2^6=3^6*8^8/8^2=3^6*8^(8-2)=3^6*8^6=(3*8)^6=24^6{(1/2)²}^6×(2^3)²=(1/2)^12*2^6=(1/2)^6*(1/2)^6*2^6=(1/2)^6*(1/2*2)^6=(1/2)^6*1=(1/2)^6