(x-6)²+√(2x-6y)²+丨y+2z丨=0
问题描述:
(x-6)²+√(2x-6y)²+丨y+2z丨=0
求(x-y)³-z³
答
∵(x-6)²+√(2x-6y)²+丨y+2z丨=0
∴x-6=0
2x-6y=0
y+2z=0
∴x=6
y=2
z=-1
∴(x-y)³-z³
=(6-2)³-(-1)³
=64+1
=65