lim X—>0 [根号(1+2x) 根号结束-1]/sinx=?
问题描述:
lim X—>0 [根号(1+2x) 根号结束-1]/sinx=?
答
方法1:无穷小替换lim {X→0} [√(1+2x) -1] / sinx = lim {X→0} [(1+2x/2 + o(x)) -1] / [x + o(x)] 无穷小替换:[√(1+2x) → 1 + 2x/2;sinx → x= lim {X→0} [x + o(x)] / [x + o(x)] = 1 方法2:罗必塔lim {X...