cos(π/6-a)=三分之根号三,sin²(a-π/6)=?
问题描述:
cos(π/6-a)=三分之根号三,sin²(a-π/6)=?
答
cos(π/6-a)=√3/3,则cos(a-π/6)=√3/3,sin²(a-π/6)=1-cos²(a-π/6)=2/3
cos(π/6-a)=三分之根号三,sin²(a-π/6)=?
cos(π/6-a)=√3/3,则cos(a-π/6)=√3/3,sin²(a-π/6)=1-cos²(a-π/6)=2/3