y=1-3cos^2(x/3+π/6)周期是
问题描述：
y=1-3cos^2(x/3+π/6)周期是
答
f(x)=3cos(1/2x－π/6) x∈R (1)f(x)=Acos(wx－π/6)x T=21/2x－π/6=2kπ x=π/3 4kπ解集是{x|x=π/3 4kπ}
y=1-3cos^2(x/3+π/6)周期是
f(x)=3cos(1/2x－π/6) x∈R (1)f(x)=Acos(wx－π/6)x T=21/2x－π/6=2kπ x=π/3 4kπ解集是{x|x=π/3 4kπ}