若x y互为相反数,则x+2x+3x.+100x+100y+99y+98y+...y的值为多少?

问题描述:

若x y互为相反数,则x+2x+3x.+100x+100y+99y+98y+...y的值为多少?

x+2x+3x.+100x+100y+99y+98y+...y=(x+y)+2(x+y)+3(x+y)+-------+100(x+y)=0