100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解
问题描述:
100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解
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答
100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198整理得52x-38y-47z=0 (1)x-y+z=3 (2)99x-99z=198即x-z=2 (3)由(3)得x=z+2 (4)代入(2)得y=2z-1 (5)代入(1)得52(z+2)-38(2z-1)-47z=0解得z=2代入(4...