一道分式计算题,

问题描述:

一道分式计算题,
计算;(a的平方/a+1)-a+1

a²/(a+1)-a+1
=a²/(a+1)-(a-1)
=a²/(a+1)-(a-1)(a+1)/(a+1)
=a²/(a+1)-(a²-1)/(a+1)
=(a²-a²+1)/(a+1)
=1/(a+1)