等差数列问题,请速回答,
问题描述:
等差数列问题,请速回答,
1.{an}是等差数列,d=1/2,S100=45,求a1+a3+a5+...+a99
2.求和1-3+5-7+...+(4n+1)-(4n+3),n∈N*
答
S100=(a1+a100)*100/2=45a1+a100=0.9a1+a3+a5+……+a99=(a1+a99)*50/2=(a1+a100-d)*25=(0.9-0.5)*25=101-3=-25-7=-2……(4n+1)-(4n+3)=-2前一项是1,5,9,……,4n+1有(4n+1-1)/4+1=n+1项所以原式=-2*(n+1)=-2n-2