几道数学题,一时忘了,

问题描述:

几道数学题,一时忘了,
1.(a-2b-3c)(a+2b-3c)
2.4x²y²-(x²+y²-z²)²
3.(a-b+c)²(b-c-a)三次方
4.若代数式4y²-2y+5的值为7,那么代数式2y²-y+1的值为?
5.(1+1/2)(1+1/2²)(1+1/2四次方)(1+1/2八次方)+1/2十五次方

1.(a-2b-3c)(a+2b-3c)=[(a-3c)-2b]*[(a-3c)+2b]=(a-3c)² + (2b)² - 2*(a-3c)*(2b)2.4x²y²-(x²+y²-z²)²=(2xy)²-(x²+y²-z²)²=(2xy + x²+y...后面几道题呢,3. (a-b+c)²(b-c-a)三次方=(-a+b-c)²(b-c-a)三次方=(b-c-a)五次方5题知道么 .另外3题的第3步3. (a-b+c)²(b-c-a)三次方=(-a+b-c)²(b-c-a)三次方=(b-c-a)五次方5.(1+1/2)(1+1/2²)(1+1/2四次方)(1+1/2八次方)+1/2十五次方=(1+2)/2 * (1+2²)/ 2² * (1+2四次方)/2四次方*(1+2八次方)/2八次方 +1/2十五次方=[ (1+2)*(1+2²)*(1+2四次方)*(1+2八次方) +1 ] / 2十五次方不好意思,2题的第3步,问错了2.4x²y²-(x²+y²-z²)²=(2xy)²-(x²+y²-z²)²=(2xy + x²+y²-z² )[2xy - (x²+y²-z²)]=-[(x+y)² -z² ][(x-y)²-z² ] =-(x+y+z)(x+y-z)(x-y+z)(x-y-z)5.[ (1+2)*(1+2²)*(1+2四次方)*(1+2八次方) +1 ] / 2十五次方=2十六次方 / 2十五次方 =2