计算:2.(3/a-2+12/a²-4)÷(2/a-2-1/a+2)

问题描述:

计算:2.(3/a-2+12/a²-4)÷(2/a-2-1/a+2)

  1. =7.68-【65‘、097,

[3/(a-2)+12/(a^2-4)]÷[2/(a-2)-1/(a+2)]
=[3(a+2)/(a-2)(a+2)+12/(a-2)(a+2)]÷[2(a+2)/(a-2)(a+2)-(a-2)/(a-2)(a+2)]
=[(3a+6+12)/(a-2)(a+2)]÷[(2a+4)/(a-2)(a+2)-(a-2)/(a-2)(a+2)]
=[(3a+18)/(a-2)(a+2)]÷[(2a+4-a+2)/(a-2)(a+2)]
=[3(a+6)/(a-2)(a+2)]÷[(a+6)/(a-2)(a+2)]
=[3(a+6)/(a-2)(a+2)]*(a-2)(a+2)/(a+6)
=3

2.(3/a-2+12/a²-4)÷(2/a-2-1/a+2)
=(3a+6+12)/(a+2)(a-2)÷(2a+4-a+2)/(a+2)(a-2)
=3