当2a+b/3a-b=2时,求代数式2a+b/2(3a-b)+3a-b/3(2a+b)(1)当2a+b/3a-b=2时,求代数式2a+b /2(3a-b) + 3a-b/3(2a+b)(2)若代数式-2^nb^m+2与4/5a^5b^2-3m是同类项,则m=___,n=___代数式-2^nb^m+2与4/5a^5b^2-3m (负2的N次方乘B的M次方+2与5分之4乘a的5次方乘B的2-3M次方)

因为(2a+b)/(3a-b)=2
所以2a+b=2(3a-b)
所以(2a+b)/2(3a-b)+(3a-b)/3(2a+b)
=2(3a-b)/2(3a-b)+(3a-b)/6(3a-b)
=1+1/6
=7/6
因为代数式-2a^nb^m+2与4/5a^5b^2-3m是同类项,
所以n=5
m=2-3m
m=1/2
所以m=1/2,n=5

(2a+b)/(3a-b)=22a+b=6a-2b4a=3ba=3b/4代入(2a+b)/[2(3a-b)]+(3a-b)/[3(2a+b)]=(2*3b/4+b)/[2(3*3b/4-b)]+(3*3b/4-b)/[3(2*3b/4+b)]=(5b/2)/(5b/2)+(5b/4)/(15b/2)=1+1/6=7/6-a^nb^(m+2)与4/5a^5b^(2-3m)是同类项则a...