√25+√36-√-64/27(x-1)²=25-(x-3)的三次方=27观察;因为(0.1)²=0.01,(0.01)²=0.0001,所以√0.01=0.1,√0.0001=0.01.若√x=a,则√0.01x=____,你有什么发现?

问题描述:

√25+√36
-√-64/27
(x-1)²=25
-(x-3)的三次方=27
观察;因为(0.1)²=0.01,(0.01)²=0.0001,所以√0.01=0.1,√0.0001=0.01.若√x=a,则√0.01x=____,你有什么发现?

√25+√36=5+6=11
-√-64/27无解,因为根号下为负数
(x-1)²=25,x-1=±5,x=6或-4
-(x-3)的三次方=27,(x-3)的三次方=-27,(x-3)=-3,x=0
观察;因为(0.1)²=0.01,(0.01)²=0.0001,所以√0.01=0.1,√0.0001=0.01。若√x=a,则√0.01x=√0.01*√x=0.1*a,

√25+√36=5+6=11
-√-64/27无根
(x-1)²=25 x-1=±5 x=6或x=-4
-(x-3)的三次方=27, -(x-3)=3 x=0
若√x=a,则√0.01x=_0.1a___

√25+√36=5+6=11-√-64/27是不是立方根?=-(-4/3)=4/3(x-1)²=25x-1=±5x=-4,x=6-(x-3)的三次方=27(x-3)³=-27x-3=-3x=0观察;因为(0.1)²=0.01,(0.01)²=0.0001,所以√0.01=0.1,√0.0001=0...

0.1a