(1又1/24-(3/8+1/6-3/4)×24)÷5

问题描述:

(1又1/24-(3/8+1/6-3/4)×24)÷5

[1又1/24-(3/8+1/6-3/4)×24]÷5
=[1+1/24-24×(3/8)-24×(1/6)+24×(3/4)]÷5
=[1+1/24-9-4+18]÷5
=145/24÷5
=29/24;