3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=03x²-(x-2)=0(2x-1)(x+3)=4x²-3x-4=0x²-3x+18=0还有一个3x²+(x-2)=2√3x

问题描述:

3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=0
3x²-(x-2)=0
(2x-1)(x+3)=4
x²-3x-4=0
x²-3x+18=0
还有一个3x²+(x-2)=2√3x

3x^2-X+2=0 deerta=(-1)^2-4X3X2=-23