求帮忙把以下几个数学公式写出具体计算步骤求解（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=a^8-1/8a^4+1/256(-3/4X^6Y^3+6/5X^3Y^4-9/10XY^5)除以3/5XY^3=-5/4X^5+2X^2Y-3/2Y^2X^M- 1/2X^m+1 - 1/5X^m + X^m+1 - 2X^m+1 = 4/5X^m- 3/2X^m+1我发现现在这辅导书真精简啊~

1、
（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=（a-1/2）^2 * (a+1/2)^2 *（a^2+1/4）^2
=（a^2-1/4）^2 *（a^2+1/4）^2
=（a^4 -1/16）^2
=a^8-1/8a^4+1/256
2、
(-3/4X^6Y^3+6/5X^3Y^4-9/10XY^5)/ [3/5XY^3 ]
=[-3/4X^6Y^3)] / [3/5XY^3 ] +[6/5X^3Y^4] / [3/5XY^3 ] - [9/10XY^5)] / [3/5XY^3 ]
=...
3、
X^M- 1/2X^m+1 - 1/5X^m + X^m+1 - 2X^m+1
= X^M - 1/5X^m - 1/2X^m+1 + X^m+1 - 2X^m+1
=（1-1/5)X^M +(-1/2 + 1-2)X^(M+1)
=4/5X^m- 3/2X^(m+1)

题目看不懂，能打的清楚点吗 你照片拍下来好了，用摄像头就行

1、利用平方差公式,完全平方式展开（a-1/2）^2（a^2+1/4）^2(a+1/2)^2=（a-1/2）^2 * (a+1/2)^2 *（a^2+1/4）^2 =（a^2-1/4）^2 *（a^2+1/4）^2 平方差公式=（a^4 -1/16）^2 平方差公式=a^8-1/8a^4+1/256 完全平方式...