x^2+y^2-2xy-3x+3y高中因式分解

问题描述:

x^2+y^2-2xy-3x+3y高中因式分解

x^2+y^2-2xy-3x+3y因式分解
把后面的(3x+3y)提一个共同的3出来
得到x^2+y^2-2xy-3(x-y)
前面的x^2+y^2-2xy可变为(x-y)^2
(x-y)^2与后面的3(x-y)共有一个(x-y)提出后变为
(x-y)(x-y-3)
就是这样,懂没?

x^2+y^2-2xy-3x+3y
=x^2-2xy+y^2-3x+3y
=(x-y)^2-3(x-y)
=(x-y)(x-y-3)

x^2+y^2-2xy-3x+3y
=(x-y)^2-3(x-y)
=(x-y-3)(x-y)

^2+y^2-2xy-3x+3y
=(x-y)²-3(x-y)
=(x-y)(x-y-3)