若x^3-6x^2+11x-6恒等于(x-1)(x^2+mx+n),求m、n的值.
问题描述：
若x^3-6x^2+11x-6恒等于(x-1)(x^2+mx+n),求m、n的值.
答
(x-1)(x^2+mx+n)=x^3+(m-1)x^2+(n-m)x-n = x^3-6x^2+11x-6
n=6
n-m=11
m-1 = -6
==>m = -5,n = 6