3(2x-1)-4(3x-5)=0 怎么解

问题描述:

3(2x-1)-4(3x-5)=0 怎么解

6x-3-12x+20=0
6x=17
x=6分之17

x等于17/6

3(2x-1)-4(3x-5)=0
6x-3-12x+20=0
-6x=-17
x=17/6

3(2x-1)-4(3x-5)=0
6x-3-12x+20=0
6x-12x=3-20
-6x=-17
x=-17/-6
x=17/6

3(2x-1)-4(3x-5)=0
6x-3-12x+20=0
12x-6x=20-3
6x=17
x=17÷6
x=2又6分之5

6x-3-12x+20=0
-6x+17=0
x=17/6