1.2[x-3]^2=[2x-5][2x+1] 2.2y^2+8y+8=0 3.-3/2x^2+x+2=0
问题描述:
1.2[x-3]^2=[2x-5][2x+1]
2.2y^2+8y+8=0
3.-3/2x^2+x+2=0
答
1
2x^2-12x+18=4x^2-8x-5
2x^2+4x-23=0
x=-1±5√2/2
2
y^2+4y+4=0
(y+2)^2=0
y=-2
3
3x^2-2x-4=0
x=(2±2√13)/6
=(1±√13)/3
答
1.2x(3-x)+^2=2-5x+2
2.2y=8y+8-2
3.-3+2-2x
答
1. 2[x-3]^2=[2x-5][2x+1] 2x^2-12x+18=4x^2+2x-10x-52x^2+4x-23=0x^2+2x=23/2[x+1]^2=25/2x+1=+/-5/根2x1=-1+5/根2x2=-1-5/根22. 2y^2+8y+8=0 y^2+4y+4=0[y+2]^2=0y=-23. -3/2x^2+x+2=0x^2-2/3x-4/3=0[x-1/3]^2=4/3...